目录
subc A, R
C AC Z OV
C
AC
Z
OV
bit T, H bit[4] L4 bit[3] H3 bit[8] X X = ((~R) + C)[7:0] {AC, L4} = A[3:0] + X[3:0] {T, H3} = A[6:4] + X[6:4] + AC {C, H} = A[7] + X[7] + T OV = C ^ T A = {H, H3, L4} Z = A ? 0 : 1
累加器A和寄存器R带借位减法,结果存储到累加器A; 注意:按照伪指令的算法,减法C标志在有借位时为0,无借位时为1;
0
1